yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Graphing shifted functions | Mathematics III | High School Math | Khan Academy


2m read
·Nov 11, 2024

We're told the graph of the function ( f(x) = x^2 ) we see it right over here in gray is shown in the grid below. Graph the function ( G(x) = (x - 2)^2 - 4 ) in the interactive graph, and this is from the shifting functions exercise on Khan Academy.

We can see we can change the graph of ( G(x) ), but let's see, we want to graph it properly. So, let's see how they relate. Well, let's think about a few things. Let's first just make ( G(x) ) completely overlap. Well, actually, that's completely easier to say than to do. Okay, there you go. Now they're completely overlapping, and let's see how they're different.

Well, ( G(x) ) if you look at what's going on here, instead of having an ( x^2 ), we have an ( (x - 2)^2 ). So, one way to think about it is when ( x = 0 ), you have ( 0^2 = 0 ); but how do you get zero here? Well, ( x ) has got to be equal to 2. ( (2 - 2)^2 = 0^2 ) if we don't look at the -4 just yet.

So, we would want to shift this graph over two to the right. This is essentially how much we shift to the right. It's sometimes a little bit counterintuitive that we have a negative there, because you might say, "Well, negative? That makes me think that I want to shift to the left." But you just have to remind yourself, "Okay, for the original graph, when it was just ( x^2 ), to get to ( 0^2 ), I just have to put ( x = 0 ). Now, to get a ( 0^2 ), I have to put in a 2." So this is actually shifting the graph to the right.

And so, what do we do with this -4? Well, this is a little bit more intuitive, or at least for me when I first learned it. This literally will just shift the graph down. Whatever your value is of ( (x - 2)^2 ), it's going to shift it down by four.

So, what we want to do is just shift both of these points down by four. So, this is going to go from the coordinate ( (5, 9) ) to ( (5, 5) ), and it's going to go from ( (2, 0) ) to ( (2, -4) ). Did I do that right? I think that's right.

Essentially, what we have going on is ( G(x) ) is ( f(x) ) shifted two to the right and four down—two to the right and four down. Notice if you look at the vertex here, we shifted two to the right and four down, and I shifted this one also. This one also, I shifted two to the right and four down.

And there you have it. We have graphed ( G(x) ), which is a shifted version of ( f(x) ).

More Articles

View All
Recognizing binomial variables | Random variables | AP Statistics | Khan Academy
What we’re going to do in this video is get some practice classifying whether a random variable is a binomial variable, and we’re going to do it by looking at a few exercises from Khan Academy. So this is a manager who oversees 11 female employees and 9 …
Dividing by 0.1 and 0.01
Let’s say we’re trying to figure out what 2 divided by 1⁄10 is. So, pause this video and see if you can have a go at that. All right, now there’s a couple of ways that we could approach this. We could just try to think of everything in terms of tenths si…
2d curl intuition
Hello everyone! So I’m going to start talking about curl. Curl is one of those very cool vector calculus concepts, and you’ll be pretty happy that you’ve learned it once you have it, for no other reason than because it’s kind of artistically pleasing. Th…
how to learn a language on your own | study tips 📚🌎
Hi guys, what’s up? It’s me, Dudy. Today, we’re gonna talk about how to learn any language on your own, and I’m gonna give you some study tips and also the methods that I’m gonna use for learning Italian because I moved to Italy and I don’t know Italian …
Using explicit formulas of geometric sequences | Mathematics I | High School Math | Khan Academy
The geometric sequence Asobi is defined by the formula, and so they say they tell us that the E term is going to be equal to 3 * -1⁄4 to the IUS 1 power. So, given that, what is a sub5, the fifth term in the sequence? So pause the video and try to figur…
Associative and commutative properties of addition with negatives | 7th grade | Khan Academy
What we’re going to do in this video is evaluate this pretty hairy expression. We could just try to do it; we could go from left to right, but it feels like there might be a simpler way to do it. I’m adding 13 here, and then I’m subtracting 13. I have a n…