yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Graphing shifted functions | Mathematics III | High School Math | Khan Academy


2m read
·Nov 11, 2024

We're told the graph of the function ( f(x) = x^2 ) we see it right over here in gray is shown in the grid below. Graph the function ( G(x) = (x - 2)^2 - 4 ) in the interactive graph, and this is from the shifting functions exercise on Khan Academy.

We can see we can change the graph of ( G(x) ), but let's see, we want to graph it properly. So, let's see how they relate. Well, let's think about a few things. Let's first just make ( G(x) ) completely overlap. Well, actually, that's completely easier to say than to do. Okay, there you go. Now they're completely overlapping, and let's see how they're different.

Well, ( G(x) ) if you look at what's going on here, instead of having an ( x^2 ), we have an ( (x - 2)^2 ). So, one way to think about it is when ( x = 0 ), you have ( 0^2 = 0 ); but how do you get zero here? Well, ( x ) has got to be equal to 2. ( (2 - 2)^2 = 0^2 ) if we don't look at the -4 just yet.

So, we would want to shift this graph over two to the right. This is essentially how much we shift to the right. It's sometimes a little bit counterintuitive that we have a negative there, because you might say, "Well, negative? That makes me think that I want to shift to the left." But you just have to remind yourself, "Okay, for the original graph, when it was just ( x^2 ), to get to ( 0^2 ), I just have to put ( x = 0 ). Now, to get a ( 0^2 ), I have to put in a 2." So this is actually shifting the graph to the right.

And so, what do we do with this -4? Well, this is a little bit more intuitive, or at least for me when I first learned it. This literally will just shift the graph down. Whatever your value is of ( (x - 2)^2 ), it's going to shift it down by four.

So, what we want to do is just shift both of these points down by four. So, this is going to go from the coordinate ( (5, 9) ) to ( (5, 5) ), and it's going to go from ( (2, 0) ) to ( (2, -4) ). Did I do that right? I think that's right.

Essentially, what we have going on is ( G(x) ) is ( f(x) ) shifted two to the right and four down—two to the right and four down. Notice if you look at the vertex here, we shifted two to the right and four down, and I shifted this one also. This one also, I shifted two to the right and four down.

And there you have it. We have graphed ( G(x) ), which is a shifted version of ( f(x) ).

More Articles

View All
Types of Radiation
At the end of the 1800s, physicists were staggered to find there was radiation coming out of all kinds of things—just dirt and rocks. Uh, the very first time this was discovered was with a jar of uranium salts that was left in a drawer overnight, and in t…
Influence of political events on ideology | AP US Government & Politics | Khan Academy
In discussing political socialization, we’ve talked a lot about factors that go into how people develop their opinions on government and politics. Your family, your friends, your demographic characteristics like your race or gender, they all contribute to…
Happy Mole Day!
Hey everybody! Rocco T. Mole here to wish you a Happy Mole Day from all of us at Khan Academy! Yes, moles! The chemistry concept, not the critter. Now, in case you’ve been living under a rock (like me), a mole is another name for Avogadro’s number which …
Marten Hat | Life Below Zero
So once I get them to this point, a lot of times I like to hang them up so I can work on them a little bit better. Very little goes to waste. You want to kind of take your time and get it started pretty good, and you can pretty much just pull straight dow…
Thin-layer chromatography (TLC) | Intermolecular forces and properties | AP Chemistry | Khan Academy
So let’s say that I have a vial of some mystery liquid right over here, and I want to start figuring out what’s going on there. The first step is to think about, is it just one substance or is it a mixture of multiple substances? The focus of this video i…
2015 AP Physics I free response 2 a and b
Some students want to know what gets used up in an incandescent light bulb when it is in series with a resistor: current, energy, or both. They come up with the following two questions: in one second, do fewer electrons leave the bulb than enter the bulb?…