yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Exponential model word problem: medication dissolve | High School Math | Khan Academy


2m read
·Nov 11, 2024

Carlos has taken an initial dose of a prescription medication. The relationship between the elapsed time T, in hours, since he took the first dose, and the amount of medication m, in milligrams, in his bloodstream is modeled by the following function:

In how many hours will Carlos have 1 milligram of medication remaining in his bloodstream? So, M of T is equal to... So we need to essentially solve for M of T, which is equal to 1 milligram, because M of T outputs whatever value it outputs, and it's going to be in milligrams. So let's just solve that.

M of T is defined; its model is an exponential function: 20 * e^(0.8T) = 1. So let's see if we can divide both sides by 20. Then we will get e^(0.8T) = 1/20, which we could write as 0.05. I have a feeling we’re going to have to deal with decimals here regardless.

So how do we solve this? Well, one way to think about it is if we took the natural log of both sides. Just as a reminder, the natural log is the logarithm base e. Let me rewrite this a little bit differently. So this says 0.05. Now I’m going to take the natural log of both sides.

So, Ln, Ln… The natural log says what power do I have to raise e to, to get to e^(0.8T)? Well, I’ve got to raise e to the negative 0.8T power. So that’s why the left-hand side simplified to this.

And that’s going to be equal to the natural log… Actually, I'll just leave it in those terms: the natural log of 0.05. Now we can divide both sides by 0.8 to solve for T. So let's do that.

We divide by 0.8, and so T is going to be equal to all this business on the left-hand side. Now we just have a T, and on the right-hand side, we have all this business, which I think a calculator will be valuable for.

Let me get a calculator out, clear it, and let’s start with 0.05. Let’s take the natural log—that’s that button right over there. The natural log, we get that value. Now we want to divide it by -0.8.

So, divided by -0.8, so let's see… They want us to round to the nearest hundredth. So it will take approximately 3.74 hours for his dosage to go down to 1 milligram.

It actually started at 20 milligrams when T equals 0. After 3.74 hours, he’s down to 1 milligram in his bloodstream. I guess his body has metabolized the rest of it in some way.

More Articles

View All
Tagging Tiger Sharks | SharkFest | National Geographic
Yeah, we’re just going to keep chumming, I think, and tee it up now. Paige has another chance to tag in a wahoo tiger shark before they gather in. As soon as I jumped in while she’s prepping the camera, I said, “Paige, this is your shot, this is your sha…
Ray Dalio on the Keys to Success
What are some of the keys to success? And beyond success, fulfilling success to a fulfilled life that you’ve seen in your experience? Well, I think you have to define what success is for yourself. I don’t think it’s the accoutrements of, um, necessarily …
Fire Starter Extraordinaire | Dirty Rotten Survival
Now we’ll find out if Dave really is the fire-making Maestro he claims to be. Depending on your environment and your resources, a very, very difficult challenge. I’m going to use everything that Dick and Johnny have in their kits, as well as what I have i…
The Berkshire Hathaway Shareholder Meeting (From Then To Now)
Warren Buffett, the CEO of Berkshire Hathaway, is without doubt the king of investing. There’s never been anyone with a track record close to his, and it’s unlikely there will be for a very, very long time. Buffett took over Berkshire Hathaway back in 196…
Motion along a curve: finding velocity magnitude | AP Calculus BC | Khan Academy
A particle moves along the curve (xy = 16) so that the y-coordinate is increasing. We underline this: the y-coordinate is increasing at a constant rate of two units per minute. That means that the rate of change of y with respect to t is equal to two. Wh…
Jacobian prerequisite knowledge
Hello everyone. So, in these next few videos, I’m going to be talking about something called the Jacobian and more specifically, it’s the Jacobian matrix or sometimes the associated determinant. Here, I just want to talk about some of the background know…