yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Writing proportional equations | Rates & proportional relationships | 7th grade | Khan Academy


2m read
·Nov 11, 2024

We're told that Justin runs at a constant rate, traveling 17 kilometers in two hours. Write an equation that shows the relationship between the distance he runs, ( d ), in kilometers and the time he spends running, ( h ), in hours. So pause this video and see if you can work through that on your own before we do it together.

All right, now there's several ways to approach this question. One way is to say, look, he's running at a constant rate, so his distance is going to be equal to some constant. Let's just call that lowercase ( k ) times the amount of time he spends running. The way that we can figure out what ( k ) is, is by using the information that they gave us. They tell us right over here that when our distance is 17 kilometers—so when our distance is 17 kilometers—that's a situation where he has been running for two hours.

So that is going to be equal to ( k ) times two hours. So what is ( k ) going to be? Pause the video again and see if you can figure it out. If you didn't figure it out the first time I asked you to pause the video…

All right, well, there's a bunch of ways to solve for ( k ), but one way is to say let's just divide both sides by two hours. So if you divide both sides by two hours, you are going to get that ( k ) is going to be equal to ( 17 ) over ( 2 ) kilometers per hour, which is ( 17 ) over ( 2 ) is ( 8.5 ) kilometers per hour.

And so if we go back to the original question, which asks us to write an equation that shows the relationship between ( d ) and ( h ), we can say that ( d ) is equal to… we now know our proportionality constant; it is ( 8.5 ) times ( h ). ( 8.5 ) times ( h ), and we're done.

If we wanted to write their units, we could write ( d ) is equal to ( 8.5 ) kilometers per hour times ( h ), which is given in hours.

More Articles

View All
How To Get Rich According to Naval Ravikant
There are a million ways to make a million dollars, and this is the sound of all. Ravi Khan does it. For those of you who don’t know, Naval Ravikant is a philosopher and entrepreneur whose insights on happiness, wealth creation, and personal growth have g…
Parametric curves | Multivariable calculus | Khan Academy
More function visualizations. So, let’s say you have a function; it’s got a single input T, and then it outputs a vector. The vector is going to depend on T. So, the X component will be T times the cosine of T, and then the Y component will be T times the…
Definite integral of radical function | AP Calculus AB | Khan Academy
So we want to evaluate the definite integral from -1 to 8 of 12 * the cube root of x dx. Let’s see, this is going to be the same thing as the definite integral from -1 to 8 of 12 * the cube root is the same thing as saying x to the 1⁄3 power dx. And so n…
Maintain | Vocabulary | Khan Academy
Ahoy word Smiths! Hold fast because this word is about keeping it steady. As she goes, “maintain” is the featured word. Oh, I maintain a steady course. Word Smith’s maintain, it’s a verb; it means to keep something the same, to provide support for someth…
The Realities of Living Off Grid | Home in the Wild
(grunts) TORI: I think that we kind of take for granted the amount of knowledge and experience that we have when we’re heading out into the backcountry. For us, it might just kind of be your regular adventure but for others, it’s a huge endeavor, and sca…
Introduction to spectroscopy | Intermolecular forces and properties | AP Chemistry | Khan Academy
In this video, we’re going to talk about spectroscopy, which is all about the interactions between light and matter. When we’re talking about light, we’re not just talking about visible light; we’re talking about electromagnetic radiation in general. So, …