yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Analyzing structure with linear inequalities: balls | High School Math | Khan Academy


2m read
·Nov 11, 2024

A bag has more green balls than blue balls, and there is at least one blue ball. Let B represent the number of blue balls, and let G represent the number of green balls. Let's compare the expressions 2B and B + G. Which statement is correct?

So, they make a bunch of comparisons between 2B and B plus G: is it greater than, less than, equal, or is there just not enough information to tell? And so, like always, pause this video and see if you can figure it out on your own before we work through it together.

All right, let's work through it together, and let's see what information they are giving us. So, this first sentence says a bag has more green balls than blue balls. We can translate that in math language as "the number of green balls is greater than the number of blue balls." It also says there is at least one blue ball. So, just translating that mathematically, we know that B is going to be greater than or equal to 1. There is at least one, but maybe more, so B is greater than or equal to one.

Now, let's see if we can somehow manipulate these so we can get to some reasonable sense of how B + G compares to 2B. Well, there are a bunch of different ways that you could approach it, and you might find a way to approach it that is different from my way. But the one that jumps out at me is, well, I know that G is greater than B. If I add a B to both sides on the left-hand side, I'm going to have B + G, and on the right-hand side, I'm going to have B + B. This right over here is 2B.

So, just like that, I know I can keep the inequality if I'm doing the same thing to both sides. If I'm adding or subtracting the same thing to both sides, just from G is greater than B, if you add B to both sides of that, we can deduce that B + G is going to be greater than B + B, or it's just going to be greater than 2B.

And that's all we need to do. Let's see which of these choices match up to that. So, let’s see: all of these have 2B on the left-hand side, so we could rewrite this as 2B is less than B + G, and that is that choice right over there.

More Articles

View All
Watch Thousands of Dogs Run Free in This Magical Sanctuary | Short Film Showcase
It was also he was the first dog who got me thinking. So what if I didn’t want to keep? Also, he wasn’t gonna find a woman, anybody else, and he’d be put down. So a hundred dogs became 200 dogs, and then 300 dogs. And then all of a sudden we thought, “Oka…
a chill day in my life
Good morning guys, it’s currently 11:20 a.m. - answering YouTube comments - okay so now it’s 12 and I think it’s enough scrolling so I’m just gonna delete all of the social media apps because it takes a lot of time. Let’s do my skincare - skincare time -…
Identifying scaled copies
What we’re going to do in this video is look at pairs of figures and see if they are scaled copies of each other. So for example, in this diagram, is figure B a scaled version of figure A? Pause the video and see if you can figure that out. There are mu…
Planar motion example: acceleration vector | Advanced derivatives | AP Calculus BC | Khan Academy
A particle moves in the XY plane so that at any time ( T ) is greater than or equal to zero, its position vector is given. They provide us the X component and the Y component of our position vectors, and they’re both functions of time. What is the particl…
Steve Jobs on Failure
Now I’ve actually always found something to be very true, which is, um, most people don’t get those experiences because they never ask. Uh, I’ve never found anybody that didn’t want to help me if I asked them for help. I always call them up. I called up,…
Volume with cross sections perpendicular to y-axis | AP Calculus AB | Khan Academy
Let R be the region enclosed by y is equal to four times the square root of nine minus x and the axes in the first quadrant. We can see that region R, and gray right over here, region R is the base of a solid. For each y value, the cross section of the so…