yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Analyzing structure with linear inequalities: balls | High School Math | Khan Academy


2m read
·Nov 11, 2024

A bag has more green balls than blue balls, and there is at least one blue ball. Let B represent the number of blue balls, and let G represent the number of green balls. Let's compare the expressions 2B and B + G. Which statement is correct?

So, they make a bunch of comparisons between 2B and B plus G: is it greater than, less than, equal, or is there just not enough information to tell? And so, like always, pause this video and see if you can figure it out on your own before we work through it together.

All right, let's work through it together, and let's see what information they are giving us. So, this first sentence says a bag has more green balls than blue balls. We can translate that in math language as "the number of green balls is greater than the number of blue balls." It also says there is at least one blue ball. So, just translating that mathematically, we know that B is going to be greater than or equal to 1. There is at least one, but maybe more, so B is greater than or equal to one.

Now, let's see if we can somehow manipulate these so we can get to some reasonable sense of how B + G compares to 2B. Well, there are a bunch of different ways that you could approach it, and you might find a way to approach it that is different from my way. But the one that jumps out at me is, well, I know that G is greater than B. If I add a B to both sides on the left-hand side, I'm going to have B + G, and on the right-hand side, I'm going to have B + B. This right over here is 2B.

So, just like that, I know I can keep the inequality if I'm doing the same thing to both sides. If I'm adding or subtracting the same thing to both sides, just from G is greater than B, if you add B to both sides of that, we can deduce that B + G is going to be greater than B + B, or it's just going to be greater than 2B.

And that's all we need to do. Let's see which of these choices match up to that. So, let’s see: all of these have 2B on the left-hand side, so we could rewrite this as 2B is less than B + G, and that is that choice right over there.

More Articles

View All
Graphing a shifted and stretched absolute value function
So we’re asked to graph ( f(x) = 2 \times |x + 3| + 2 ). And what they’ve already graphed for us, this right over here, is the graph of ( y = |x| ). Let’s do this through a series of transformations. So the next thing I want to graph, let’s see if we ca…
Generating Power on Mars | MARS: How to Get to Mars
So, power on Mars is going to be very important, and it will have to have the ability to run the microwave oven, along with the oxygenator and everything else that we’re going to need to survive. You need power; every civilization needs power. It’s what w…
Introduction to the coordinate plane
You’re probably familiar with the notion of a number line where we can take a number and associate it with a point on the number line. So for example, the number 2, I would go, I would start at 0, and I’d go 1, 2 to the right, and I would end up right ove…
Coolest Concert Ever? Hear Ice Instruments Play Beautiful Music | Short Film Showcase
Is there anyone here who does not understand Swedish? Okay, it was about 20 years ago when I built my first ice musical instrument on top of a mountain. I tightened the strings, and I plucked on the wires, and I heard the sound coming out from inside the…
Warren Buffett: This investment will increase your net worth by 50%
If they just they increase their value at least 50 percent. So, I was recently watching an interview with Warren Buffett, and he said something so impactful I just had to make a video on it. Buffett recommended an investment anyone can make that will inst…
Writing a quadratic function from solutions | Algebra 1 (TX TEKS) | Khan Academy
We’re told a quadratic function ( f ) has two real solutions ( x = -3 ) and ( x = 5 ) that make ( f(x) = 0 ). Select the equations that could define ( f ) in standard form. So, pause this video and have a go at that before we do this together. All right,…