yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Example diving a unit fraction by a whole number


2m read
·Nov 11, 2024

So let's see if we can figure out what one-third divided by five is. And I'll give you a hint: try to draw out one-third of a whole and then divide it into five equal sections. Pause this video and try to do that.

All right, now let's try to work through it together. And to help us, as I promised or as I suggested, I guess we said, let's draw a third. So I will represent a whole by that square right over there.

Now let me split it up into three equal sections. So this is all hand drawn with the aid of a computer, so it's not going to be perfect. But let's say that that is three equal sections. It's roughly three equal sections. I didn't do it perfectly, but you hopefully get the idea.

And so one third would be one of those three equal sections. So that's a third right over there that I have just shaded in, and I want to divide it into five. Or I want to divide it by five, I should say. So let's do that.

To divide it by five, I'm going to divide it into five equal sections. If I'm doing, if I'm dividing that one into five equal sections, let me just divide all of the thirds into five equal sections. I'm essentially just going to make five rows here: one, and I'm going to eyeball it, so it's going to be approximate: two, three, and then four and five equal sections.

Notice I now split this whole into one, two, three, four, five rows of equal height. Now, if I go to my original third and divide it by five, I would be left with this right over here. But what fraction is this of the whole?

Well, what I've done now is I've split my whole into 15 equal sections. How do I know that? Well, I could count them: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15. Or you could just say, look, I had one, two, three thirds, and now each of those have been split into one, two, three, four, five equal sections.

So three times five is 15. So each of these is a fifteenth. And so the one-third divided by five is just one of those fifteenths. So that right over there is one of those fifteenths. So this is going to be equal to one fifteenth, and we are done.

More Articles

View All
Why Society Peaked in 2016
In many ways, the world sucks right now. We’re more divided than we’ve ever been. There’s more chaos, war, and unrest all around the globe. Smartphones and social media that used to act as an escape have turned into digital prisons, trapping us into an en…
YC SUS: Gustaf Alströmer and Eric Migicovsky discuss growth tactics
Exciting! Welcome to another week of Startup School. I’m joined this week by Gustav. You want to tell us a little bit about yourself? Maybe your background? Sure! So I work here at YC as a partner. I’ve been here for two and a half years. Before that, I …
The First Monotheistic Pharaoh | The Story of God
Amid the remains of dozens of pharaohs, Egyptologist Salma Ikram is going to help me find one whose name is Akhenaten. There he is! Yep, he thought that there were too many gods and not enough focus on him. There will need to be an important god whom onl…
Khan Stories: Claudia
My name’s Claudia and I’m currently a freshman at MIT. I’m from South Florida and now my journey continues here. My family is from the Azores Islands, which are in the middle of the Atlantic. Just knowing that where my family comes from and the lack of e…
Is this private jet worth $20,000,000?
This is a $20 million plane, and this is Steve. He’s selling it. Should we take a look inside? Let’s go! As soon as you walk in, we have this fantastic galley. It’s got a really big counter space. On the right side here, we have crew rest. This is import…
Worked example: Using the reaction quotient to find equilibrium partial pressures | Khan Academy
For the reaction of iron II oxide plus carbon monoxide goes to solid iron and carbon dioxide, the equilibrium constant Kp is equal to 0.26 at 1000 Kelvin. Our goal is to find the equilibrium partial pressures of our two gases, carbon monoxide and carbon d…