yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Second derivatives | Advanced derivatives | AP Calculus AB | Khan Academy


2m read
·Nov 11, 2024

Let's say that Y is equal to 6 over x squared. What I want to do in this video is figure out what is the second derivative of Y with respect to X.

If you're wondering where this notation comes from for a second derivative, imagine if you started with your Y and you first take a derivative. We've seen this notation before, so that would be the first derivative. Then we want to take the derivative of that, so we then want to take the derivative of that to get us our second derivative. That's where that notation looks comes from. It looks like we're having you have a d squared d times d, although you're not really multiplying them.

Applying the derivative operator twice, it looks like you have a dx squared. Once again, you're not multiplying them; you're just applying the operator twice. But that's where that notation actually comes from.

Well, let's first take the first derivative of Y with respect to X. To do that, let's just remind ourselves that we just have to apply the power rule here. We can just remind ourselves, based on the fact that Y is equal to 6 X to the negative 2.

So let's take the derivative of both sides of this with respect to X. With respect to X, I'm going to do that, and so on the left-hand side, I'm going to have dy/dx is equal to, now on the right-hand side, take our negative 2, multiply it times the 6; it's going to get negative 12 X to the negative 2 minus 1, which is X to the negative 3.

Actually, let me give myself a little bit more space here. So this is negative 12 X to the negative 3. Now, let's take the derivative of that with respect to X. So I'm going to apply the derivative operator again.

The derivative with respect to X, now the left-hand side gets the second derivative of Y with respect to X is going to be equal to, well, we just used the power rule again. Negative 3 times negative 12 is positive 36 X times X to the, well, negative 3 minus 1 is negative 4 power, which we could also write as 36 over X to the fourth power.

And we're done.

More Articles

View All
Unwanted Visitors- Deleted Scene | Life Below Zero
What I’m doing is the last people that were here, they’re supposed to bring some of their own tarps, spread them out, use their stuff. Um, but instead they use mine. Common courtesy would dictate cleaning them. That’s what I ask: hey, if you’re going to u…
Meaning of absolute value
In this video, we’re going to introduce ourselves to the idea of absolute value, which you can view as how far you are from zero. So, for example, let’s say that we have a bunch of people living on a street, and let’s say that we say that the school is a…
Can causality be established from this study? | Study design | AP Statistics | Khan Academy
A gym that specializes in weight loss offers its members an optional dietary program for an extra fee. To study the effectiveness of the dietary program, a manager at the gym takes a random sample of 50 members who participate in the dietary program and 5…
Invertible matrices and transformations | Matrices | Precalculus | Khan Academy
We have two two by two matrices here. In other videos, we talk about how a two by two matrix can represent a transformation of the coordinate plane, of the two-dimensional plane, where this, of course, is the x-axis, and this, of course, is the y-axis. W…
Stoichiometry: mass-to-mass and limiting reagent | Chemistry | Khan Academy
Let’s solve a cool stoichiometry problem. Consider the chemical reaction where we have propane that burns with oxygen, giving us water and carbon dioxide. Okay, now if you’re conducting this reaction, our question is how much propane in grams is needed to…
Steve Elkins Q&A | Explorer
[Music] There’s a heat there, inscriptions right here. There are, yes, we hit P, guys. Wow, this is awesome! I’ve been doing this for almost 20 years. This project captured my imagination, and to me, it’s a privilege and very exciting to be able to disco…