yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Explained: Beaker Ball Balance Problem


2m read
·Nov 10, 2024

You have made your prediction, and now it is time to see what happens when I release the balance. Ready? In three, two, one.

The balance tips towards the right, towards the hanging, heavier ball. But why does this happen? Well, the best way I can think of to explain this is that both balls displace the same amount of water. So they both experience the same upward buoyant force, which is equal to the weight of the water they displace. That is just Archimedes' Principle.

But by Newton’s Third Law, that means there must be equal and opposite forces down on the water in both beakers. So you would think that both beakers would get heavier by this same amount. Now, for the hanging ball, the beaker does get heavier by this amount because the buoyant force is now supporting some of the weight that used to be supported by this tension in the string. But it is now reduced, and so the beaker actually has more weight.

But for the ping pong ball, the downward force on the water is almost entirely counteracted by the upward force of the tension in that string on the bottom of the beaker. Therefore, the weight of this beaker only increases by the weight of the ping pong ball itself, whereas for the hanging ball, the weight increases by the weight of the water it displaces. So, obviously, this beaker is going to end up being heavier.

Now I want to propose an additional experiment. What if instead of tethering the ping pong ball to the base of this beaker, I just got a free ping pong ball and submerged it with my finger, just barely under the surface of the water? In that case, what do you think would happen when the scale was allowed to rotate? Would it tilt down A) towards the hanging acrylic ball or B) down towards the ping pong ball, which is now just barely submerged under the water or C) would the balance remain perfectly balanced?

So I want you to make your selection, make your prediction by leaving a comment starting with either A, B, or C, and then giving me your explanation. And I will tally up the votes and let you know the answer next time.

More Articles

View All
The Venus Project: mistakes that advocates make
So there’s been an exchange between Stefan Molyneux and Peter Joseph on YouTube lately, and I’ve been commenting on both videos and communicating with advocates of the Venus Project. In this video, I’ll try to correct some of the most important misconcept…
Subtracting with integer chips | Integers: Addition and subtraction | 7th grade | Khan Academy
Let’s say that we want to figure out what negative 8 minus negative 2 is. Now, there’s a lot of ways to approach this, but what we’re going to focus on in this video is to really build the intuition, and we’re going to do that with something called number…
Mean (expected value) of a discrete random variable | AP Statistics | Khan Academy
[Instructor] So, I’m defining the random variable x as the number of workouts that I will do in a given week. Now right over here, this table describes the probability distribution for x. And as you can see, x can take on only a finite number of values: z…
Government Shutdown Imminent, Rates Spike, Stocks Collapse
Back here at home, time is running out to avoid a government shutdown. Billions of Americans could go without paychecks, including members of the military. The country is headed for a shutdown, and everyone should prepare as such. Big guys, it’s Graham h…
Geometric constructions: perpendicular line through a point off the line | Geometry | Khan Academy
What I have here is a line, and I have a point that is not on that line. My goal is to draw a new line that goes through this point and is perpendicular to my original line. How do I do that? Well, you might imagine that our compass will come in handy; i…
Integrating power series | Series | AP Calculus BC | Khan Academy
So we’re told that ( f(x) ) is equal to the infinite series we’re going from ( n = 1 ) to infinity of ( \frac{n + 1}{4^{n + 1}} x^n ). What we want to figure out is what is the definite integral from 0 to 1 of this ( f(x) ). And like always, if you feel i…