yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Explained: Beaker Ball Balance Problem


2m read
·Nov 10, 2024

You have made your prediction, and now it is time to see what happens when I release the balance. Ready? In three, two, one.

The balance tips towards the right, towards the hanging, heavier ball. But why does this happen? Well, the best way I can think of to explain this is that both balls displace the same amount of water. So they both experience the same upward buoyant force, which is equal to the weight of the water they displace. That is just Archimedes' Principle.

But by Newton’s Third Law, that means there must be equal and opposite forces down on the water in both beakers. So you would think that both beakers would get heavier by this same amount. Now, for the hanging ball, the beaker does get heavier by this amount because the buoyant force is now supporting some of the weight that used to be supported by this tension in the string. But it is now reduced, and so the beaker actually has more weight.

But for the ping pong ball, the downward force on the water is almost entirely counteracted by the upward force of the tension in that string on the bottom of the beaker. Therefore, the weight of this beaker only increases by the weight of the ping pong ball itself, whereas for the hanging ball, the weight increases by the weight of the water it displaces. So, obviously, this beaker is going to end up being heavier.

Now I want to propose an additional experiment. What if instead of tethering the ping pong ball to the base of this beaker, I just got a free ping pong ball and submerged it with my finger, just barely under the surface of the water? In that case, what do you think would happen when the scale was allowed to rotate? Would it tilt down A) towards the hanging acrylic ball or B) down towards the ping pong ball, which is now just barely submerged under the water or C) would the balance remain perfectly balanced?

So I want you to make your selection, make your prediction by leaving a comment starting with either A, B, or C, and then giving me your explanation. And I will tally up the votes and let you know the answer next time.

More Articles

View All
WHY IT'S BETTER TO BE SINGLE | STOIC INSIGHTS ON THE BENEFITS OF SINGLE LIFE | STOICISM INSIGHTS
Welcome back to Stoicism Insights, where we dive deep into the wisdom of the ancient Stoics to uncover timeless truths for modern living. Today we have something truly special in store for you. Have you ever wondered about the power of solitude, the freed…
Exploring Dog-Human Communication
What if you could communicate with your pet? If they could just tell you how much they love you, how when you leave the house to go to work, it feels like they’ve just spent a week without you? In the 1970s, a gorilla named Koko learned sign language. Wi…
2015 AP Physics 1 free response 4
Two identical spheres are released from a device at time equals zero from the same height ( h ), as shown above. Sphere A has no initial velocity and falls straight down. Sphere B is given an initial horizontal velocity of magnitude ( v_0 ) and travels a …
How parameters change as data is shifted and scaled | AP Statistics | Khan Academy
So I have some data here in a spreadsheet. You could use Microsoft Excel or you could use Google spreadsheets, and we’re going to use the spreadsheet to quickly calculate some parameters. Let’s say this is the population. Let’s say this is—we’re looking a…
15 Things to Avoid During the Holidays
Hey there, relaxer. Wherever you’re watching this, you know, you’re probably celebrating some sort of holiday, whether you’re religious or not. It’s still a time when the year comes to an end. It’s a closing chapter for most people around the world. A tim…
What Will We Miss?
Hey, Vsauce. Michael here. And the year 6009 will be the very first year since 1961 that a year, when written in Hindu-Arabic numerals, can be inverted and still look the same. But you and I probably won’t live long enough to enjoy the year six thousand a…