yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Worked example: p-series | Series | AP Calculus BC | Khan Academy


2m read
·Nov 11, 2024

So we have an infinite series here: one plus one over two to the fifth plus one over three to the fifth, and we just keep on going forever. We could write this as the sum from n equals one to infinity of 1 over n to the 5th power, 1 over n to the 5th power.

Now, you might recognize—notice when n is equal to 1, this is 1 over 1 to the 5th; that's that over there. And we could keep on going. Now you might immediately recognize this as a p series, and a p series has the general form of the sum going from n equals 1 to infinity of 1 over n to the p, where p is a positive value.

So, in this particular case, our p for this p series is equal to five; p is equal to five. Now you might already recognize under which conditions for a p series does it converge or diverge. It's going to converge. It's going to converge when your p is greater than one, which is clearly the case in this scenario right over here. Our p is clearly greater than one.

We would diverge; we would diverge if our p is greater than zero and less than or equal or less than or equal to 1. This would be a divergence. So if this was like 0.9 here, or if this was a, you know, three-fourths, then we would be diverging. So at least for this one, we are convergent.

Let's do another one of these. All right, so here you might again recognize this as a p series. Let me rewrite this infinite sum. So this is the sum from n equals 1 to infinity of 1 over—let's see—we have square root of 2, square root of 3. So you could use this as 2 to the one-half, 3 to the one-half, 4 to the one-half. So it's 1 over n to the one half.

Notice this is when n is equal to one: one over one to the one half is one. One over two to the one half, well that's this right over here, and we keep on going on and on and on. Well, in this case, we still have a p series. We have one over n to some power, and that power is positive, but notice in this case our p falls between zero and one.

So one half is our p, so p for our p series is equal to one-half, and that's between zero and one. Remember, we're divergent—divergent when our p is greater than zero and less than or equal to one, which was clearly the case right over here. So this is going to be divergent.

More Articles

View All
Conditions for IVT and EVT: graph | Existence theorems | AP Calculus AB | Khan Academy
So we have the graph of ( y ) is equal to ( h ) of ( x ) right over here and they ask us, does the intermediate value theorem apply to ( h ) over the closed interval from negative one to four? The closed interval from negative one to four right over here…
Supporting Education Around the Okavango Delta | National Geographic
[Music] My name is Collective. The noun for hippo is a pod of hippo. We’ve invited 10 local teachers from Beta Primary School to demystify a lot of those misconceptions that animals and wildlife can be an additive to their experience. Many of them are fr…
Why Tik Tokers Are BROKE
9.2 million followers, 70 million likes, 100 million plus, right? It’s just how much I’ve made. This is KSI, massive content creator, huge following, partially owns Prime, which just became the UFC’s official drink, among other things. Despite its massive…
Robinhood Just Got Cancelled
What’s up, you guys? It’s Graham here! So, you might have recently noticed that something has been missing from the channel lately, and no, it’s not the free stock you can get worth all the way up to $50 down below in the description. Instead, it’s some …
RECESSION ALERT: The FED Just Crashed The Stock Market
Welp, I thought this is going to be a normal day. As I woke up, opened my computer, took a sip of coffee, expected to get more recommendations on Johnny Depp’s trial, and was immediately hit by the headline: GDP fell by 1.4 percent, leading to the concern…
Strategies for subtracting more complex decimals with tenths
Some more examples subtracting decimals. So let’s say we want to figure out what 2 - 1.2 is. Pause this video and see if you can calculate this. So, there’s multiple ways to tackle this. One way is you could say, look, this is the same thing as 2 - 1, 2 …