yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Finding equivalent ratios in similar quadrilaterals | Grade 8 (TX) | Khan Academy


2m read
·Nov 10, 2024

We are told Lucas dilated quadrilateral ABCD to create quadrilateral WXYZ. So it looks like he rotated and zoomed in or made it or expanded it to get this other quadrilateral. The fact that we used these types of transformations like a dilation and it looks like a quad rotation as well, it tells us that these are similar to each other. They are similar, similar quadrilaterals.

So based on that, which proportion must be true? Pause this video and see if you can work that through on your own before we do this together.

All right, now let's do this together. So for my brain, and given that I have access to a very nice palette of colors, what I want to do is color the corresponding sides the same. So let's think about side CD here. We know that this point, or this angle right over here with one arc corresponds to this angle, and then this other angle with the double arcs is right over there.

So this side YZ corresponds to side CD. Then we could say, all right, going from the right angle over here to the point C, that would correspond to going from the right angle to the point Y in this other quadrilateral. Maybe I'll use red for this one. Going from B to A would correspond to going from X to W.

These are corresponding sides, and then last but not least, side AD corresponds to side ZW. That'll help us keep track of what's going on here. So this first one has the length of segment CD. The length of segment CD. The ratio between that and BC, and BC is my blue one, or my teal color, I should say.

BC, they're saying that's the same as XY, which is in teal, to YZ. Well, this one isn't feeling right. In order for this to be true, you would have to flip one of these ratios because, once again, my pink one to blue one on this quadrilateral should be the same. It should be pink to blue on the other quadrilateral, not blue to pink. That is one way to think about it, so let's rule out that one.

Now, let's see. We have the ratio between CD and BC is the same as the ratio between XY and WX. Well, this isn't even using corresponding sides right over here, so let's rule that one out. All right, next we have the ratio between CD and YZ, so those are corresponding sides. Then they're saying that should be equal to BC over WZ. BC over WZ. Well, WZ is not corresponding to BC, so I'll rule that out.

So just deductive reasoning would tell us that this is likely our choice. But let's work through it. So they're saying the ratio of CD to YZ, CD to YZ, is the same as the ratio of BC, BC to XY. So yes, this is ratios of corresponding sides, so this proportion must be true.

More Articles

View All
Worked example: Motion problems with derivatives | AP Calculus AB | Khan Academy
A particle moves along the x-axis. The function x of t gives the particle’s position at any time t is greater than or equal to zero, and they give us x of t right over here. What is the particle’s velocity v of t at t is equal to 2? So, pause this video,…
a productive day in the life vlog
Hi guys, it’s me, Ruri. So yeah, I just woke up. I head to the bathroom, I took a very cold shower, and now I’m doing my skincare routine. After doing my skincare, I’ll make myself some coffee and start studying. Peace. Oh, why does my hair look this weir…
The Fascinating Lives of Bleeding Heart Monkeys (Part 1) | Nat Geo Live
So National Geographic asked us here tonight to tell you about a day in the life of gelada monkeys and what it’s like to live alongside them. For the past decade, the vet and I have spent years living alongside this species in a unique kind of alpine out-…
The Stoic Guide To Overcoming The Desire To Escape Everything | STOICISM INSIGHTS
Isn’t it a bit strange that in this vast world we often stick to the same small corners where we were born? Here we are, on this huge spinning globe, and many of us never venture far from where our journey began. Think about it: how often do we find ourse…
Hydrogen bonding | Intermolecular forces and properties | AP Chemistry | Khan Academy
Let’s talk about hydrogen bonds. Depicted here, I have three different types of molecules. On the left, I have ammonia; each ammonia molecule has one nitrogen bonded to three hydrogens. In the middle, I have something you’re probably very familiar with. I…
IP addresses and DNS | Internet 101 | Computer Science | Khan Academy
Hi, my name is Paula, and I am a Software Engineer at Microsoft. Let’s talk about how the internet works. My job relies on networks being able to talk with one another, but back in the 1970s, there was no standard method for this. It took the work of Vinc…