yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Subtracting rational expressions: factored denominators | High School Math | Khan Academy


3m read
·Nov 11, 2024

Pause this video and see if you can subtract this magenta rational expression from this yellow one. All right, now let's do this together. The first thing that jumps out at you is that you realize that these don't have the same denominator, and you would like them to have the same denominator.

You might say, well, let me rewrite them so that they have a common denominator. A common denominator that will work will be one that is divisible by each of these denominators, so it has all of the factors of each of these denominators. Lucky for us, each of these denominators are already factored.

Let me just write the common denominator. I'll start rewriting the yellow expression. So you have the yellow expression—actually, let me just make it clear; I'm going to write both the yellow one, and then you're going to subtract the magenta one. Whoops, I'm saying yellow but drawing in magenta.

So you have the yellow expression, which I'm about to rewrite. Actually, I'm going to make a longer line. So the yellow expression minus the magenta one—minus the magenta one right over there. Now, as I mentioned, we want to have a denominator that has all the common factors.

The common denominator has to be divisible by both this yellow denominator and this magenta one. So it's got to have the z plus 8 in it, it's got to have the 9z minus 5 in it, and it's also got to have both of these well. We already accounted for the 9z minus 5. So it has to be divisible by z plus 6.

Notice, just by multiplying the denominator by z plus 6, we're now divisible by both of these factors. Both of these factors, because 9z minus 5 was a factor common to both of them. If you were just dealing with numbers when you were just adding or subtracting fractions, it works the exact same way.

All right, so what will the numerator become? Well, we multiply the denominator times z plus 6, so we have to do the same thing to the numerator. It's going to be negative z to the third times z plus 6. Now let's focus over here.

We want the same denominator, so we could write this as z plus 8 times z plus 6 times 9z minus 5. And these are equivalent; I've just changed the order that we multiply, and that doesn't change their value. If we multiplied the—so we had a 3 on top before, and if we multiply the denominator times z plus 8, we also have to multiply the numerator times z plus 8.

So there you go. This is going to be equal to—this is going to be equal to, actually, I'll just make a big line right over here. This is all going to be equal to—we have our probably don't need that much space. Let me see, maybe that may be about that much. So I'm gonna have the same denominator.

I'll just write it in a neutral color now: z plus eight times nine z minus five times z plus 6. So over here, just in this blue color, we want to distribute this negative z to the third.

Negative z to the third times z is negative z to the fourth. Negative z to the third times 6 is minus 6 z to the third. Now, this negative sign right over here, actually instead of saying negative z—negative of this entire thing, we could just say plus the negative of this.

Or another way of thinking about it, you could view this as negative 3 times z plus 8. So we could just distribute that. So let's do it. Negative 3 times z is negative 3 z, and negative 3 times 8 is negative 24. There you go; we are done.

We found a common denominator, and once you have a common denominator, you can just subtract or add the numerators. Instead of viewing this as minus this entire thing, I viewed it as adding and then having a negative 3 in the numerator, distributing that, and then these—I can't simplify it any further.

Sometimes you'll do one of these types of exercises, and you might have two second-degree terms or two first-degree terms or two constants or something like that, and then you might want to add or subtract them to simplify it. But here, these are all have different degrees, so I can't simplify it any further.

And so we are all done.

More Articles

View All
Why your $1 is REALLY worth $5 (Real Estate Investing Mind Trick)
This is also why when you’re investing in real estate, how you should look at every one dollar is actually being worth five dollars. Because this is how much it’s actually truly worth. So this is something I catch myself doing all the time and I thought I…
A Suspiciously Expensive Delivery | To Catch a Smuggler: South Pacific | National Geographic
Auckland International Airport processes 21 million passengers every year and climbing. Customs and Immigration have just been alerted to a visiting Lithuanian woman with quite a history. Officer James is keen to take on the case. It looks like she had so…
2015 AP Physics 1 free response 1c
Let’s now tackle part C. They tell us block three of mass m sub 3, so that’s right over here, is added to the system, as shown below. There is no friction between block three and the table. All right, indicate whether the magnitude of the acceleration of …
Private jet trading floor 😳
So this is our trading floor. I was going to say when I walked in, it looks like a proper trading floor. So this is my version of a Wall Street trading floor. Each desk looks like a cockpit. It comes from basically a Bard Global jet cockpit. It’s done al…
Solving 3-digit addition in your head | 2nd grade | Khan Academy
[Voiceover] What I want to do in this video is go over some techniques for doing mental addition. Now, if I saw something like 355 plus 480, if you have some paper around, you could write these numbers down and do your traditional addition, but you might …
Le Châtelier's principle | Reaction rates and equilibrium | High school chemistry | Khan Academy
Let’s imagine a reaction that is in equilibrium: A plus B can react to form C plus D, or you could go the other way around. C plus D could react to form A plus B. We assume that they’ve all been hanging around long enough for this to be in equilibrium, so…