yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Comparing exponent expressions


2m read
·Nov 11, 2024

So we are asked to order the expressions from least to greatest. This is from the exercises on Khan Academy. If we're doing it on Khan Academy, we would drag these little tiles around from least to greatest, least on the left, greatest on the right. I can't drag it around because this is just a picture.

I'm going to evaluate each of these and then I'm going to rewrite them from least to greatest. So let's start with (2) to the third minus (2) to the first. What is that going to be? (2) to the third minus (2) to the first. If you feel really confident, just pause this video and try to figure out the whole thing—order them from least to greatest.

Well, (2) to the third, that is (2) times (2) times (2), and then (2) to the first, well that's just (2). So (2) times (2) is (4), times (2) is (8). Minus (2), this is going to be equal to (6). So this expression right over here could be evaluated as being equal to (6).

Now what about this right over here? What is this equal to? Well, let's see. We have (2) squared plus (3) to the (0). (2) squared is (2) times (2), and anything to the (0) power is going to be equal to (1).

It's an interesting thing to think about what zero to the zero power should be, but that'll be a topic for another video. Here we have (3) to the zero power, which is clearly equal to (1). So we have (2) times (2) plus (1). This is (4) plus (1), which is equal to (5).

So the second tile is equal to (5). And then (3) squared. Well, (3) squared, that's just (3) times (3). (3) times (3) is equal to (9).

So if I were to order them from least to greatest, the smallest of these is (2) squared plus (3) to the (0) power. That one is equal to (5), so I'll put that on the left. Then we have this thing that's equal to (6), (2) to the third power minus (2) to the first power. And then the largest value here is (3) squared. So we would put that tile, (3) squared, we will put that tile on the right, and we're done.

More Articles

View All
This is why I'll NEVER flip houses...
Lots of you guys, it’s Graham here. So, as many of you know, I’ve been working full-time in real estate since 2008 as a real estate agent, which means I’m kind of getting old now. Now, if you’re doing that, I’ve helped my own clients flip properties for a…
Creative biology at work | High school biology | Khan Academy
[Music] Hi everyone, Salcon here. From finding novel cures for a seemingly incurable disease to diagnosing what’s going on with someone, if you’re a physician or a nurse, you can imagine there’s incredible creativity in biology. And don’t take my word fo…
Negative definite integrals | Integration and accumulation of change | AP Calculus AB | Khan Academy
We’ve already thought about what a definite integral means. If I’m taking the definite integral from ( a ) to ( b ) of ( f(x) \, dx ), I can just view that as the area below my function ( f ). So, if this is my y-axis, this is my x-axis, and ( y ) is equ…
The Most Controversial Problem in Philosophy
Do not hit the like button! Or the dislike button, at least not yet. I want you to consider a problem that’s been one of the most controversial in math and philosophy over the past 20 years. There is no consensus answer. So I want you to listen to the pro…
The Evergrande Crisis Continues...
Alright guys, welcome back! It’s time for an update video on Evergrande. I told you it would be a crazy week, and it certainly was. However, Evergrande is still standing, at least for now. So let’s get up to speed on exactly where Evergrande is at with th…
2015 AP Physics 1 free response 1a
Two blocks are connected by a string of negligible mass that passes over a massless pulley that turns with negligible friction. It is shown in the figure above. We see that the mass M2 of block 2 is greater than the mass M1 of block 1. The blocks are rele…