yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Analyzing relationships between variables using tables and equations | 6th grade | Khan Academy


2m read
·Nov 10, 2024

We're told Rava is researching an electric car. She finds this graph which shows how much range, measured in kilometers, the car gains based on charging time. All right, and they say first fill in the missing values in the table below. If you are so inspired, pause this video and see if you can have a go at that as well.

All right, well, they give us a few points, and I'm assuming these are points on a line. We can see when the charging time is 15 minutes, the range is 180. So we can see when the charging time is 15 minutes, the range is 180. We can see when the charging time is 30 minutes, the range is 360 km. So I could write that there.

Then we see when the charging time is 45 minutes, the range is 540 km. So that's all nice, but then they give us a few other points here. They say what happens when we are at T = 10 or T = 1, which aren't easy to pick out here. But this is where it might be useful if we assume that this is a line. What is the relationship between these?

So let's see. To go from 15 to 180, it looks like you're multiplying by 12. To go from 30 to 360, it looks like we're multiplying by 12. To go from 45 to 540, it looks like we are multiplying by 12. So assuming K is just going to be 12 * T, we know that when T equals 1, K is 12, and when T equals 10, 10 * 12 is 120.

All right, now the second part they say write an equation Rava can use to find out how much charging time T it takes to gain any number of kilometers in range K. All right, well, we already established a relationship. We said that K is equal to 12 times whatever T is; that's what we just established in this table up here.

But that's not what they want. They want to find out how much charging time T it takes to gain any number of kilometers in range K. So what we need to do here is solve for T. So let's divide both sides by 12 to just have T by itself on the right-hand side, and we are going to be left with T is equal to K over 12.

T is equal to K over 12, and notice you could put any number of kilometers of range in here, and you're essentially just going to divide it by 12, and that will give you how much charging time. I guess this would assume an infinitely large battery, which we know doesn't exist, but for the sake of this problem here, we have it. Here is the equation Rava can use.

More Articles

View All
How to sell private jets to billionaires!
My name is Steve Varsano, and I have a company called The Jet Business. We’re involved with the buying and selling of corporate jets. I live in the UK; I work in the UK. I set up my business in the UK, but my business is global. The final purchase price …
Meaningfully composing functions | Composite and inverse functions | Precalculus | Khan Academy
We’re told that Jalen modeled the following relationships about their bus ride. So there’s three functions here; we have their inputs and we have their outputs. So, function P: the input is the time the bus arrives, given as lowercase b, and the output i…
Safari Live - Day 206 | National Geographic
This program features live coverage of an African safari and may include animal kills and caucuses. Viewer discretion is advised. Good afternoon and welcome to a stripey start to our sunset Safari on a rather windy afternoon. It is a little bit breezy, Ar…
Your Body's Molecular Machines
These are tiny molecular machines, and they are doing this inside your body - right now. To understand why, we have to zoom out. Every day, in an adult human body, 50 to 70 billion of your cells die. Either they’re stressed, or damaged, or just old. But t…
Interpreting equations graphically (example 2) | Mathematics III | High School Math | Khan Academy
Let F of T be ( e^{2T} - 2T^2 ) and H of T be ( 4 - 5T^2 ). The graphs of Y = F(T) and Y = H(T) are shown below. So, Y = F(T) is here in green, so this is really ( Y = e^{2T} - 2T^2 ). We see F(T) right over there, and Y = H(T) is shown in yellow. Alrigh…
Multiplying 10s | Math | 4th grade | Khan Academy
Let’s multiply 40 times 70. So, 40 times we have the number 70. So, we could actually list that out, the number 70, 40 different times and add it up, but that’s clearly a lot of computation to do, and there’s got to be a faster way. So, another way is …