yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Analyzing relationships between variables using tables and equations | 6th grade | Khan Academy


2m read
·Nov 10, 2024

We're told Rava is researching an electric car. She finds this graph which shows how much range, measured in kilometers, the car gains based on charging time. All right, and they say first fill in the missing values in the table below. If you are so inspired, pause this video and see if you can have a go at that as well.

All right, well, they give us a few points, and I'm assuming these are points on a line. We can see when the charging time is 15 minutes, the range is 180. So we can see when the charging time is 15 minutes, the range is 180. We can see when the charging time is 30 minutes, the range is 360 km. So I could write that there.

Then we see when the charging time is 45 minutes, the range is 540 km. So that's all nice, but then they give us a few other points here. They say what happens when we are at T = 10 or T = 1, which aren't easy to pick out here. But this is where it might be useful if we assume that this is a line. What is the relationship between these?

So let's see. To go from 15 to 180, it looks like you're multiplying by 12. To go from 30 to 360, it looks like we're multiplying by 12. To go from 45 to 540, it looks like we are multiplying by 12. So assuming K is just going to be 12 * T, we know that when T equals 1, K is 12, and when T equals 10, 10 * 12 is 120.

All right, now the second part they say write an equation Rava can use to find out how much charging time T it takes to gain any number of kilometers in range K. All right, well, we already established a relationship. We said that K is equal to 12 times whatever T is; that's what we just established in this table up here.

But that's not what they want. They want to find out how much charging time T it takes to gain any number of kilometers in range K. So what we need to do here is solve for T. So let's divide both sides by 12 to just have T by itself on the right-hand side, and we are going to be left with T is equal to K over 12.

T is equal to K over 12, and notice you could put any number of kilometers of range in here, and you're essentially just going to divide it by 12, and that will give you how much charging time. I guess this would assume an infinitely large battery, which we know doesn't exist, but for the sake of this problem here, we have it. Here is the equation Rava can use.

More Articles

View All
SEO Advice from SurveyMonkey Director of SEO and Growth, Eli Schwartz
All righty, let’s jump right into it. So, first question: Does SEO still matter in 2018 or can companies ignore it and focus on other channels? This is a question I get asked a lot, and I’ve been asked this question in many years past. Sometimes, the quo…
How I Bought This House For $0
I’m very proud to say that this property right here was free. It cost me zero dollars. I was able to buy an income-generating property here in Los Angeles for nothing, and I think it’s at this point that people are supposed to comment, “It’s free real est…
How to find a mentor - the RIGHT way
What’s up you guys, it’s Graham here. So this is probably one of the most important topics that I’m going to be discussing so far, and it’s about mentoring. I feel like so many people are so caught up right now in trying to find a mentor. They think that …
Scaling perimeter and area example 2 | Transformational geometry | Grade 8 (TX) | Khan Academy
We’re told quadrilateral A was dilated by a scale factor of 2⁄3 to create quadrilateral B. Complete the missing measurements in the table below. So like always, pause this video and then we will do this together. Try to do it yourself, and then we’ll do i…
Why I Stopped Buying Real Estate
What’s up, Graham? It’s guys here. So, you probably clicked on the video because you saw the title and wanted to see if it was clickbait after all. For nearly my entire adult life, I’ve been known as the real estate guy. It’s what I did right after high s…
Applying the chain rule and product rule | Advanced derivatives | AP Calculus AB | Khan Academy
What we’re going to do in this video is try to find the derivative with respect to X of (x^2 \sin(X)) all of that to the third power. And what’s going to be interesting is that there are multiple ways to tackle it. I encourage you to pause the video and …