yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Calculating Gravitational Attraction


2m read
·Nov 10, 2024

Most people recognize that the gravitational force attracts them towards the Earth and keeps them stuck on the planet. But the gravitational force does so much more than that; it attracts any object with mass towards any other object with mass.

So, for example, this table is attracted gravitationally to the chair, and the chair is attracted to the table. This is a beautiful symmetric idea because it means that every object you can see around you is attracted to you gravitationally, and you are attracted to it. The reason we don't notice that attraction is because the force is so small.

So today, I'd like to show you how to calculate the size of the force of attraction between any two masses. In this example, we'll call this mass one and this object mass two. The force is proportional to mass one, so the larger mass one is, the bigger the force is. The force is also proportional to mass two; the bigger that mass is, the bigger the force is.

Now, the force is what we call inversely proportional to the distance between them squared. So if the distance between their centers is called r, then the further apart they are, the smaller this force is, and that makes sense. Now, to make this a true equality, we need to add Big G, the universal gravitational constant. This is just a number, a constant of the universe, which tells us how strong the gravitational force is. This number G is 6.67 * 10^-11 Newton m² per kilogram².

As you can see, it's a pretty small number, so the force is going to be relatively small. So let's do an example. Let's calculate the force of attraction between me and, say, João.

"Hello, this is my twin brother."

"Hi everybody!"

So the force F is going to be equal to the gravitational constant 6.67 * 10^-11 times my mass, which is 70 kg, times João's mass, which is 70 kg.

"Oh no, I thought you were putting on a little weight!"

"No, hey, 70 kg."

And divide by the distance between us, which is what, do you say, about 1.5 m?

"Don't forget to square it!"

"I wasn't going to forget!"

Okay, so this works out to be 1.45 * 10^-7 Newtons. There is a tenth of a millionth of a Newton attracting me and João. And that's not all, dude. Now, a Newton is the amount of force...

More Articles

View All
Why Patience is Power | Priceless Benefits of Being Patient
Buddha and his disciples once embarked on a long journey. Exhausted from a long day of walking, they decided to stop and rest near a lake. Buddha asked his youngest and most impatient disciple to walk to the lake and bring him some water, so he did. But w…
A live message from Sal on school closures
All right, so we are where I start in a few minutes, probably a few seconds. You don’t mind them, Twitter? Okay, hello! Well, thanks everyone for joining. The whole idea of this livestream, and we’re thinking of doing this as regularly as we can, is obvio…
Stop Buying Stocks | The Market Crisis Just Got Worse
What’s up, Grandma’s guys? Here, so I know I always preach the age-old sayings of “Buy and Hold.” You can’t predict the market; time in the market beats timing the markets. The market can remain irrational longer than you could remain solvent, and the sto…
Checking Out the New Digs! | The Boonies
[Music] Is there anything back there? Say, is there anything back there, Joe? “See something promising looking up here. This could be… could lead us to something good. Maybe not, I don’t know.” Below the grid, Joe Ray’s Bridge has allowed him to venture…
Conjugate acid–base pairs | Chemical reactions | AP Chemistry | Khan Academy
In this video, we’re going to be talking about conjugate acid-base pairs. We’re going to introduce the idea of a conjugate acid-base pair using an example reaction. The example reaction is between hydrogen fluoride, or HF, and water. So, hydrogen fluorid…
Factoring using polynomial division: missing term | Algebra 2 | Khan Academy
We’re told the polynomial ( p(x) ) which is equal to this has a known factor of ( x + 6 ). Rewrite ( p(x) ) as a product of linear factors. Pause this video and see if you can have a go at that. All right, now let’s work on this together. Because they gi…