yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Interpreting units in formulas | Mathematics I | High School Math | Khan Academy


2m read
·Nov 11, 2024

Consider the formula P is equal to W / T where P represents power, W represents the work and has units of joules. Joules can be expressed as kilogram times meter squared per second squared, and T represents time and has units of seconds.

When you get to physics class, you'll get very familiar with things like joules, which can be represented as kilogram times meters per second squared, and things like power. But here we're going to learn to manipulate these units so that they make sense.

So it says to select an appropriate measurement unit for power. What we've seen multiple times in our mathematical careers is that, on a certain level, you can manipulate units in a lot of the same ways that you would manipulate variables or numbers.

So, if power is equal to work divided by time, we could also say that the units for power are going to be the units for work divided by the units for time.

The units for work right over here is joules. So we could write it's going to be joules per... and then the unit for time is seconds. So you might want to say it's joules per second. But we don't see joules per second as a choice here, so we probably want to expand out joules as being kilogram meter squared per second squared.

So let's do that. This is going to be equal to joules. We can rewrite joules as kilogram times meter squared over second squared, and we're going to divide all of that by seconds.

And so what's that going to be? Well, we could rewrite this. This is going to be kilograms... and I'm intentionally trying not to skip any steps. Kilograms times meter squared per second squared, and dividing by seconds is the same thing as multiplying by 1/seconds, so times 1 over seconds.

If we treat these units the way that we might treat things like variables, this would be equal to, in the numerator, we would have kilogram times meter squared or kilogram times square meters.

In the denominator, you have seconds. You have seconds to the third power. So a unit for power, one way to express the units for power, could be kilogram meter squared per second cubed. And we see that this is this first choice: kilogram meter squared per second cubed.

More Articles

View All
Parents, learn how to boost writing skills with Khanmigo
Hey parents, we know that trying to help your kids with their essays can often feel like navigating through an unknown city without a map. But don’t worry, we’re here to provide the compass that you need. We’re proud to present our latest Kigo feature: ac…
After Largest Dam Removal in U.S. History, This River Is Thriving | National Geographic
Shinook 6055, coo, 115. We got 108. It depends on the species, but we have a broad range, and they’re all kids, from infants to basically teenagers. Seeing the evolution is what it’s ended up being. In particular, in the Nearshore, it’s been a dramatic t…
Meet the Intimidating Eel That Mates For Life | National Geographic
Okay, so this is a wool feel. As anything named after a wolf would suggest, they are intimidating master predators. You may see the way this guy chomps down on a sea urchin like it just doesn’t even feel its spines on its throat. His teeth are pretty worn…
10 Things That Turn Ordinary People Into Entrepreneurs
There is no such thing as a born entrepreneur, but once you get into contact with certain things in life, your mindset changes. These are 10 things that turn ordinary people into entrepreneurs. Welcome to Alux. First up, a desire to take the future into …
The Stock Market Is FREE MONEY | DO THIS NOW
What’s up, Grandma’s guys? Here, so let’s face it, the stock market is easy money. In fact, in just the last 12 months, both the S&P 500, the Dow Jones, and the NASDAQ are all up over 30 percent. Nearly every single stock you can imagine is up substan…
Orbital motion | Physics | Khan Academy
If a satellite has just the right velocity, then we can make sure that the force of gravity will always stay perpendicular to that velocity vector. In that case, the satellite will go in a perfect circular orbit, because the gravitational force will act l…