yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Using right triangle ratios to approximate angle measure | High school geometry | Khan Academy


2m read
·Nov 10, 2024

We're told here are the approximate ratios for angle measures: 25 degrees, 35 degrees, and 45 degrees.

So, what they're saying here is if you were to take the adjacent leg length over the hypotenuse leg length for a 25-degree angle, it would be a ratio of approximately 0.91. For a 35-degree angle, it would be a ratio of 0.82. And then they do this for 45 degrees and they do the different ratios right over here.

So, we're going to use the table to approximate the measure of angle D in the triangle below. So pause this video and see if you can figure that out.

All right, now let's work through this together. Now, what information do they give us about angle D in this triangle? Well, we are given the opposite length right over here. Let me label that: that is the opposite leg length, which is 3.4.

And we're also given, what is this right over here? Is this adjacent or is this a hypotenuse? You might be tempted to say, well, this is right next to the angle, or this is one of the lines, or it's on the ray that helps form the angle. So maybe it's adjacent. But remember, adjacent is the adjacent side that is not the hypotenuse, and this is clearly the hypotenuse.

It is the longest side; it is the side opposite the 90-degree angle. So this right over here is the hypotenuse.

So, we're given the opposite leg length and the hypotenuse length, and so let's see which of these ratios deal with the opposite and the hypotenuse.

And if we, let's see, this first one is adjacent and hypotenuse. The second one here is hypotenuse—sorry, opposite and hypotenuse. So that's exactly what we're talking about; we're talking about the opposite leg length over the hypotenuse length.

So, in this case, what is going to be our opposite leg length over our hypotenuse leg length? It's going to be 3.4 over 8. Three point four over eight, which is approximately going to be equal to... let me do this down here.

This is eight goes into three point four. Eight doesn't go into three. Eight goes into 34 four times. Four times eight is 32. If I subtract, and I could scroll down a little bit, I get a two. I can bring down a zero. Eight goes into 20 two times, and that's about as much precision as any of these have.

And so it looks like for this particular triangle and this angle of the triangle, if I were to take a ratio of the opposite length and the hypotenuse length, opposite over hypotenuse, I get 0.42. So that looks like this situation right over here.

So that would imply that this is a 25-degree angle—approximately.

More Articles

View All
The Next Great Depression - How To Prepare
What’s gram up? It’s guys, you here, and it’s official: as of today, the bear market just hit a brand new low. Most people believe the economy is about to fall even further. For instance, Michael Burry just went on record to say that the S&P 500 still…
Night Search for Whip Spiders | Explorers In The Field
Most of us see gigantic insects and politely head in the other direction. Other, more adventurous types, like behavioral neuroscientist and National Geographic explorer Werner Bingman, are apt to crawl around the Costa Rica rainforest in the dark, trying …
Bond length and bond energy | AP Chemistry | Khan Academy
If you were to find a pure sample of hydrogen, odds are that the individual hydrogen atoms in that sample aren’t just going to be separate atoms floating around. Many of them, and if not most of them, would have bonded with each other, forming what’s know…
Catch of the Week - Something to Prove | Wicked Tuna
Airing it under control, the best time forward. Bump, bump, quick, good, neutral, great! Now it’s a tuna. Having this fish hooked up amongst the fleet is great. If we can land this fish, it would be the first one landed. It could be a good shot in the ar…
Position vector valued functions | Multivariable Calculus | Khan Academy
Let’s say I have some curve C and it’s described; it can be parameterized. I can’t say that word as, let’s say, x is equal to X of t, y is equal to some function y of T, and let’s say that this is valid for T between A and B, so T is greater than or equal…
Help Khan Academy this giving season
Hi everyone, Sal KH here from Khan Academy. I’m here to ask if you’re in a position to do so to seriously think about supporting Khan Academy and its mission of free, world-class education for anyone, anywhere. As you can imagine, that is a very big miss…