yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Darren's Great Big Camera - Smarter Every Day 21


2m read
·Nov 3, 2024

Today on Smarter Every Day, you're gonna learn about big rockets and big cameras. Is it going now? Woah! [Rushing air] Woohoo! Yeah! Oh! Hey, it's me, Destin. I'm at the U.S. Space & Rocket Center with my new friend Darren, who's got a great big camera. So I contacted him when I found out he was doing a road trip, and I knew a great big camera's needed to film great big things, and one of the coolest things in America is the Saturn V rocket. So Darren agreed. [Music]

(Darren) I had to do a lot of research before I could even build this camera. There are certain things that you have to know ahead of time, because you don't want to get to a point where you've invested time and money and then suddenly you realize that you've miscalculated, you know, the image circle for your lens, and suddenly, you're not covering the entire piece of film. So I had to do research on lenses - if they were big enough; which ones were big enough. I like detail, and I'm getting more detail than I think you can get with any digital camera, so... You know, when you got a piece of film that's 504 square inches, you get a lot of information from those photos.

Okay, we're gonna shoot f/90 this time.

(Destin) f/90? - Yeah. So I'm going to meter one more time, just to double-check. And I have 90 2/3 in 8 seconds. It's roughly... The numbers - the green numbers - are what I'm looking at. So 64 is here, but then we're going two more stops. You can see how... It's 64 and it keeps going. So that's 128. That's 90. Yeah, it was just a lot of calculations. Knowing how much chemistry to use to develop a sheet... a film that large. Um... and then also being able to calculate how much extra coverage I would have that would give me the... the movements that I would use on the camera. I had never had to really think about, you know, things like image circle and bellows draw. So there was a little bit of math that hadn't been used in a while.

I wanted to make every shot count, and now that I've got a 70-pound camera, it's more pressure, I suppose. But it's also more rewards, bigger rewards, so... The challenges are always part of the fun. [Motorcycle engine roaring]

Captioning in different languages welcome. Please contact Destin if you can help.

More Articles

View All
$25,000 vs. $25,000,000
This is what a $25 million a year salary looks like versus a $25,000 a year salary. About 20% of Americans live on this amount of money or less. I want to show you the lifestyles of people who make this much money versus this much money and everything in …
Cumulative geometric probability (less than a value) | AP Statistics | Khan Academy
Lilliana runs a cake decorating business for which 10% of her orders come over the telephone. Let’s see ( C ), the number of cake orders Lilliana receives in a month until she first gets an order over the telephone. Assumed a method of placing each cake …
Metaverse: Beyond Human
Imagine a world where you wake up, head to the office in the morning, to a party with friends in the evening, and then a live concert at midnight, all while sitting in the warmth of your home or from the comfort of your bed. That might just be part of hum…
RFS: LLMs for manual back office processes in legacy enterprises
One thing I’d love to see more startups working on is the use of LLMs to automate complex back office processes in large enterprises. So, for example, in a bank, you might have a customer service team answering loads and loads of queries from customers. …
Does Water Swirl the Other Way in the Southern Hemisphere?
Derek: A couple of years ago my friend Destin and I wanted to definitively answer the question: does water actually swirl the opposite direction down the drain in the other hemisphere? At the time, I was living in Sydney, Australia, and Destin was in Hunt…
Evaluating composite functions: using graphs | Mathematics III | High School Math | Khan Academy
So we have the graphs of two functions here. We have the graph (y) equals (f(x)) and we have the graph (y) is equal to (g(x)). And what I wanna do in this video is evaluate what (g(f(…)). Let me do the (f(…)) in another color. (f(-5)) is… (f(-5)) is… An…