yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Drawing particulate models of reaction mixtures | Chemical reactions | AP Chemistry | Khan Academy


2m read
·Nov 10, 2024

In a previous video, we used a particulate model like this to understand a reaction—not just understand the reaction, but to balance the chemical reaction as well. When I hand drew these particles, the atoms in this particulate model here, I tried to draw it pretty close to their actual relative sizes. Carbon atoms are a little bit bigger than oxygen atoms, and they're both a lot bigger than hydrogen atoms.

What we're going to do in this video is extend our understanding using a particulate model to start to visualize what actually might go on in a mixture of some of these reactant molecules. So, what I have here on the left-hand side are the various molecules. I have two methane molecules here, and I have three water molecules. What I want to do with you is draw what we would expect to see after the reaction. I encourage you, like always, to pause this video and see if you can have a go at that—maybe with a pencil and paper—at least just try to imagine it in your head before I do this with you.

All right, now let's do this together. Now we know that for every methane and every water, we're going to produce one carbon monoxide and three molecular hydrogens. Each of those molecules of hydrogen has two hydrogens in them. So let's just say that this one and this one react; they're going to produce one carbon monoxide. I'm going to try to draw the relative sizes roughly right, so one carbon monoxide, and then they're going to produce six hydrogen atoms that are going to be in three hydrogen molecules. So let’s do that: that’s two and four, and then I’ll just do one here, and then six.

All right, so I took care of this one and this one, and now we can imagine that maybe this water molecule reacts with this methane molecule, and so that would produce another carbon monoxide. Let me draw that roughly at the right size—another carbon monoxide molecule and three more hydrogen molecules or, for a total of six more hydrogens. So that's one and two, and three.

And now we have this water right over here that had no one to react with in this situation—had no partner—and so that's just going to be a leftover reactant molecule. So let me just draw it right over here. So that water could be right over here, and so this was a useful way of starting to visualize what might be going on. Remember, this is happening at a very high temperature; they’re all bouncing around, etc. And then, when they react, you might get this. But then this water molecule has no one to react to, so it is—you could view it as a leftover after the reaction.

More Articles

View All
Time past between two clock faces
We are asked how much time has passed from the time on the left, so right over here, to the time on the right, which we see right over here. They say that the time passed is less than 12 hours. So like always, pause this video and see if you can answer th…
2015 AP Physics 1 free response 1b
All right, let’s tackle part B now. Derive the magnitude of the acceleration of block 2. Express your answer in terms of m1, m2, and g. And like always, try to pause the video and see if you can work through it yourself. We already worked through part on…
How Bird Wings Work (Compared to Airplane Wings) - Smarter Every Day 62
[Music] Hey, it’s me D, and welcome back to Smarter Every Day. So, some of my favorite things to learn are those things that I’ve seen for several years, and I’ve made a lot of observations, and I kind of think I get it, you know? I mean, like really get …
The feeling of wanting to leave everything behind...
It’s quite ironic that in a world as vast as ours, we often find ourselves clinging to just a tiny part of it. Often, we die in the same place we came into existence, surrounded by roughly the same people. Somehow, we’re expected to remain close to our ro…
Applying the chain rule and product rule | Advanced derivatives | AP Calculus AB | Khan Academy
What we’re going to do in this video is try to find the derivative with respect to X of (x^2 \sin(X)) all of that to the third power. And what’s going to be interesting is that there are multiple ways to tackle it. I encourage you to pause the video and …
Sal answers questions from attendees at his Schoolhouse.world series
I’d love to answer any questions y’all have about anything. Um, uh, raise your hands or uh, probably raising your hand is the best, is the best way to do it. Yes, Kai, ask your question. All right, thanks. No, thanks again Saul for taking your time and a…