yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Drawing particulate models of reaction mixtures | Chemical reactions | AP Chemistry | Khan Academy


2m read
·Nov 10, 2024

In a previous video, we used a particulate model like this to understand a reaction—not just understand the reaction, but to balance the chemical reaction as well. When I hand drew these particles, the atoms in this particulate model here, I tried to draw it pretty close to their actual relative sizes. Carbon atoms are a little bit bigger than oxygen atoms, and they're both a lot bigger than hydrogen atoms.

What we're going to do in this video is extend our understanding using a particulate model to start to visualize what actually might go on in a mixture of some of these reactant molecules. So, what I have here on the left-hand side are the various molecules. I have two methane molecules here, and I have three water molecules. What I want to do with you is draw what we would expect to see after the reaction. I encourage you, like always, to pause this video and see if you can have a go at that—maybe with a pencil and paper—at least just try to imagine it in your head before I do this with you.

All right, now let's do this together. Now we know that for every methane and every water, we're going to produce one carbon monoxide and three molecular hydrogens. Each of those molecules of hydrogen has two hydrogens in them. So let's just say that this one and this one react; they're going to produce one carbon monoxide. I'm going to try to draw the relative sizes roughly right, so one carbon monoxide, and then they're going to produce six hydrogen atoms that are going to be in three hydrogen molecules. So let’s do that: that’s two and four, and then I’ll just do one here, and then six.

All right, so I took care of this one and this one, and now we can imagine that maybe this water molecule reacts with this methane molecule, and so that would produce another carbon monoxide. Let me draw that roughly at the right size—another carbon monoxide molecule and three more hydrogen molecules or, for a total of six more hydrogens. So that's one and two, and three.

And now we have this water right over here that had no one to react with in this situation—had no partner—and so that's just going to be a leftover reactant molecule. So let me just draw it right over here. So that water could be right over here, and so this was a useful way of starting to visualize what might be going on. Remember, this is happening at a very high temperature; they’re all bouncing around, etc. And then, when they react, you might get this. But then this water molecule has no one to react to, so it is—you could view it as a leftover after the reaction.

More Articles

View All
Adjective order | The parts of speech | Grammar | Khan Academy
So, Grom Marians, if you’re a native English speaker, the phrase “French old white house” might seem a little weird to you. If you’re not a native English speaker, it might not. This is something that I didn’t really know about before I started preparing …
Indus Valley Civilization | Early Civilizations | World History | Khan Academy
As we’ve talked about in multiple videos, some of the earliest civilizations we have found have been around river valleys, and that is no coincidence. Because some of the first agriculture emerged around river valleys, and the agriculture supported higher…
Introduction to real gases | Intermolecular forces and properties | AP Chemistry | Khan Academy
In several other videos, we have talked about the ideal gas law, which tells us that pressure times volume is going to be equal to the number of moles times the ideal gas constant times the temperature measured in Kelvin. Now, in all of our studies of the…
Refraction and frequency | Waves | Middle school physics | Khan Academy
When light is going through a uniform medium like the air, or as we know, light can go through vacuum, so nothing at all, we imagine it going in a straight line. But we see something really interesting happening here when it hits this glass prism. I know …
Crowdfunding campaign: Give Me Your Ball
Why don’t we start by telling? By introducing. Why don’t we start by having? Let’s start. My name is Thomas K. A couple of years ago, I made the film “George Ought to Help.” Last year, with the help of crowdfunding, I made the film “Edgar the Exploiter.”…
Innovation Requires Decentralization and a Frontier
Innovation requires a couple of things. One of the things that it seems to require is decentralization. I don’t think it’s a coincidence that the Athenian city-states, the Italian city-states, or even the United States, when it was more free-form and invo…