yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Visually determining vertical asymptotes | Limits | Differential Calculus | Khan Academy


2m read
·Nov 11, 2024

Given the graph of yal ( f(x) ) pictured below, determine the equations of all vertical asymptotes.

Let's see what's going on here. So it looks like interesting things are happening at ( x = -4 ) and ( x = 2 ). At ( x = -4 ), as we approach it from the left, the value of the function just becomes unbounded right over here. It looks like as we approach ( x = -4 ) from the left, the value of our function goes to infinity. Likewise, as we approach ( x = -4 ) from the right, it looks like our value of our function goes to infinity.

So I'd say that we definitely have a vertical asymptote at ( x = -4 ). Now let's look at ( x = 2 ). As we approach ( x = 2 ) from the left, the value of our function once again approaches infinity or it becomes unbounded.

Now, from the right, we have an interesting thing. If we look at the limit from the right right over here, it looks like we're approaching a finite value. As we approach ( x = 2 ) from the right, it looks like we’re approaching ( f(x) = -4 ). But just having a one-sided limit that is unbounded is enough to think about this as a vertical asymptote.

The function is not defined right over here, and as we approach it from just one side, we are becoming unbounded. It looks like we're approaching infinity or negative infinity. So that by itself, this unbounded left-hand limit or left side limit by itself is enough to consider ( x = 2 ) a vertical asymptote.

So we can say that there's a vertical asymptote at ( x = -4 ) and ( x = 2 ).

More Articles

View All
Limits at infinity of quotients with trig | Limits and continuity | AP Calculus AB | Khan Academy
So let’s see if we can figure out what the limit as x approaches infinity of cosine of x over x squared minus one is. And like always, pause this video and see if you can work it out on your own. Well, there’s a couple of ways to tackle this. You could j…
Shouldn't We Just Copy Warren Buffett's Portfolio?
I could not come up with these ideas on my own. I came up with this idea from Warren and Charlie, and I copied it. So, one of the most important models that you can adopt is the model of cloning. When you see someone doing something smart, uh, just incorp…
Properties of buffers | Acids and bases | AP Chemistry | Khan Academy
A buffer solution consists of a significant amount of a weak acid and its conjugate base. Let’s say we have a generic weak acid HA and its conjugate base A⁻. We’re going to use some particulate diagrams to try to understand how buffers work. So for our f…
Warren Buffett’s Most Iconic Interview Ever
Secular approach who have also been very successful. Let’s take Warren Buffett of Omaha, Nebraska. If you would put $10,000 in 1965 into his company, Berkshire Hathaway, you would have 1 million today. Warren was a chapter in my 1972 book, Super Money, so…
Missing numbers in three digit subtraction
Let’s say that we are told that 495 is equal to 621 minus blank. What would blank be? Pause this video and see if you can figure that out. Okay, now let’s do this together. One technique is to try to visualize this on a number line. 495 is what you get w…
Virtual Mindfulness Retreat with Khan Academy and Headspace
And the intention for today’s hour is really just to relax, um, just to unwind. Not a lot of information coming at you, just embodied practices. And I know that a lot of you probably have commitments at home right now, maybe kids coming in. And so really …