yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Explicit Laplacian formula


3m read
·Nov 11, 2024

So let's say you have yourself some kind of multivariable function, and this time let's say it's got some very high dimensional input. So X1, X2, on and on and on, up to, you know, X sub n for some large number n.

Um, in the last couple videos, I told you about the Lassan operator, which is a way of taking in your scalar valued function f, and it gives you a new scalar valued function. It's kind of like a second derivative thing because it takes the divergence of the gradient of your function f. So the gradient of f gives you a vector field, and the divergence of that gives you a scalar field.

What I want to show you here is another formula that you might commonly see for this Leian. So first, let's kind of abstractly write out what the gradient of f will look like.

So we start by taking this Dell operator, which is going to be a vector full of partial differential operators: partial with respect to X1, partial with respect to X2, and kind of on and on and on up to partial with respect to whatever that last input variable is. You take that, that whole thing, and then you just kind of imagine multiplying it by your function.

Uh, so what you end up getting is all the different partial derivatives of f, right? It's partial of f with respect to the first variable, and then kind of on and on and on up until you get the partial derivative of f with respect to that last variable X sub n.

And the divergence of that, and just to save myself some writing, I'm going to say you take that n operator and then you imagine taking the dot product between that whole operator and this gradient vector that you have here.

What you end up getting is, well, you start by multiplying the first components, which involves taking the partial derivative with respect to X1, that first variable, of the partial derivative of f with respect to that same variable.

So it looks like the second partial derivative of f with respect to that first variable, so the second partial derivative of f with respect to X1, that first variable. And then you imagine kind of adding what the product of these next two items will be.

For very similar reasons, that's going to look like the second partial derivative of f with respect to that second variable, partial X2 squared. And you do this to all of them, and you're adding them all up until you find yourself, you know, doing it to the last one.

So you've got plus and then a whole bunch of things, and you'll be taking the second partial derivative of f with respect to that last variable, partial of X sub n. This is another format in which you might see the Lan, and oftentimes it's written, um, kind of compactly.

So people will say the Lan of your function f is equal to, and then using Sigma notation, you'd say the sum from I is equal to 1 up to, you know, 1, 2, 3, up to n. So the sum from that up to n of your second partial derivatives, partial squared of f with respect to that e variable.

So, you know, if you were thinking in terms of three variables, often X1, X2, X3, we instead write XYZ, but it's common to more generally just say X sub I. So this, this here is kind of the alternate formula that you might see for the Lan.

Personally, I always like to think about it as taking the divergence of the gradient of f because you're thinking about the gradient field, and the divergence of that kind of corresponds to maxima and minima of your original function.

Which is what I talked about in the initial intuition of the Lassan video. But this, this formula is probably a little more straightforward when it comes to actual computations.

And oh wait, sorry, I forgot I squared there, didn't I? So, uh, partial X squared. So this is the second derivative. Yeah, so summing, summing these, uh, second partial derivatives, and you can probably see this is kind of a more straightforward way to compute a given example that you might come across.

And it also makes clear how the Lan is kind of an extension of the idea of a second derivative. See you next video.

More Articles

View All
Road to Extinction | Years of Living Dangerously
Climate change here is disrupting a way of life that has allowed humans and animals to live side-by-side for centuries. Yes, the were in what is a key leader within the African Wildlife Foundation, one of the premier conservation groups on the continent. …
Rent inflation, San Francisco affordable housing crises
The absence of dividends doesn’t just affect the legitimacy of stocks and stock investors; it proudly has the worst impact on low-income people who struggle to pay rent. The reality is, when companies hoard profits and end up with too much money to play w…
Example punnet square for sex-linked recessive trait | High school biology | Khan Academy
Hemophilia is an X-linked recessive trait that affects blood clotting. If someone has hemophilia, their blood has trouble clotting. If a carrier woman and a hemophiliac man have a daughter, what is the percent chance that she, the daughter, will have hemo…
Equations with rational expressions | Mathematics III | High School Math | Khan Academy
So we have a nice little equation here dealing with rational expressions, and I encourage you to pause the video and see if you can figure out what values of x satisfy this equation. All right, let’s work through this together. The first thing I’d like t…
Dividing quadratics by linear expressions with remainders: missing x-term | Algebra 2 | Khan Academy
This polynomial division business is a little bit more fun than we expected, so let’s keep going. So let’s say that, I guess again, someone walks up to you in the street and says, “What is x squared plus 1 divided by x plus 2?” So pause this video and hav…
The Physics Of Basketball | StarTalk
We’re exploring the physics of basketball, featuring my interview with NBA All-Star Kareem Abdul-Jabbar. Check it out. A rebound—in basketball, you have to get a sense of how the thing is going to bounce before the thing makes that bounce so that you can…