yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Worked example: Calculating molar mass and number of moles | AP Chemistry | Khan Academy


3m read
·Nov 10, 2024

We are asked to calculate the number of moles in a 1.52 kilogram sample of glucose. So, like always, pause this video and try to figure this out on your own. This periodic table of elements will prove useful.

All right. Now, if we're trying to figure out the number of moles, remember, a mole is really, you could view it as a quantity of something. If I said a dozen of something, you'd say, "Oh, that's 12 of that thing." If I say a mole of something, I'm saying that's Avogadro's number of that thing.

So, we have a 1.52 kilogram sample of our molecule in question, of glucose. If we can figure out the mass per mole, or in other words, think about it— the molar mass of glucose, well then we just divide the mass of our sample by the mass per mole, and we'll know how many moles we have.

So, what is the molar mass of glucose? Well, to figure that out, and that's why this periodic table of elements is useful, we just have to figure out the molar mass of the constituent elements. So, if we first look at carbon, we see from this periodic table of elements that carbon has a molar mass of 12.01 grams per mole.

We've talked about in other videos, you could view this 12.01 as the relative atomic mass of a carbon atom or as the average atomic mass of a carbon atom, or what's useful—and this is where Avogadro's number is valuable—if you have Avogadro's number of carbons, it is going to have a mass of 12.01 grams.

So, carbon has a molar mass of 12.01 grams per mole. Now we can think about hydrogen in the same way. Hydrogen has a molar mass of 1.008 grams per mole. And then, last but not least, we have oxygen here. Oxygen, we can see from our periodic table of elements, has a molar mass of 16.00 grams per mole.

So now we have all the information we need from our periodic table of elements. The molar mass of glucose is going to be six times the molar mass of carbon plus 12 times the molar mass of hydrogen plus six times the molar mass of oxygen.

So, it's going to be six times 12.01 grams per mole plus 12 times 1.008 grams per mole plus, every molecule of glucose has 6 oxygens, plus six times 16.00 grams per mole.

Six times 12.01 plus 12 times 1.008 plus 6 times 16 is equal to— and if we're thinking about significant figures here, the molar mass of hydrogen goes to the thousands place, but we only go to the hundredths for carbon and for oxygen.

We're adding all these up together, so it's going to be 180 point—I can only go to the hundredths place for significant figures—so 180.16.

So, that's equal to 180.16 grams per mole. We could say grams of glucose C6H12O6 per mole of glucose C6H12O6.

Then we can use this 1.52 kilograms to figure out how many moles we have. So, if we start off with 1.52 kilograms of glucose, so that's C6H12O6. First, we can convert it to grams because here our molar mass is given in terms of grams.

So, times—we're going to want kilograms in the denominator and grams in the numerator. How many grams are there per kilogram? Well, we have 1000 grams for every one kilogram. So, when you multiply these two out, this is going to give you the number of grams we have of glucose, which would be 1520.

If you have your mass in terms of grams, you can then divide by your molar mass, or you could view it as multiplying it by the moles per gram. For every one mole of glucose C6H12O6, we have 180.16 grams of glucose C6H12O6.

This is going to get us— we get 1.52 times 1000 is equal to— this is the number of grams of glucose we have. Then, we're going to divide by 180.16. Divide by 180.16 gives us this number.

And let's see if we see significant figures. We have three significant figures here, we have five here, so we want to round it to three significant figures. So, it will be 8.44 moles of glucose.

So, our kilograms cancel with our kilograms, and then our grams of glucose cancel with our grams of glucose, and we are left with 8.44 moles of glucose, moles of C6H12O6, and we are done.

More Articles

View All
Future Computers Will Be Radically Different (Analog Computing)
For hundreds of years, analog computers were the most powerful computers on Earth, predicting eclipses, tides, and guiding anti-aircraft guns. Then, with the advent of solid-state transistors, digital computers took off. Now, virtually every computer we u…
Marginal and conditional distributions | Analyzing categorical data | AP Statistics | Khan Academy
Let’s say that we are trying to understand a relationship in a classroom of 200 students between the amount of time studied and the percent correct. So, what we could do is we could set up some buckets of time studied and some buckets of percent correct. …
WTF Happened To Santa Monica, California?!
Don’t steal from my store. Recent violent attacks in Santa Monica and a growing homeless population have shaken neighbors and businesses. A series of high-profile crimes over the past several weeks became part of a showdown between the city and businesse…
15 Signs You’re Burned Out, Not Lazy
Over 70% of professionals feel burnt out at some point, yet many dismiss it as mere laziness. But the great news about burnout is that it’s solvable. The bad news about laziness is that, in this video, we’re about to call you out. Here are 15 signs you’re…
How to get ahead of 99% of people
If you want an extraordinary life, you can’t live like an ordinary person. Matt Graham said, “the people that criticize you for being exceptional are those that have already accepted the fact that they’re going to be mediocre.” A YouTuber with a million s…
Ordering rational numbers in context | Grade 8 (TX) | Khan Academy
During basketball practice, four students practiced their free throw shots. The table below shows the proportion of free throws they each make. Let’s see. Simone made 68 of their free throws. David made Z 68 H hundreds, I guess I could say, of his free t…