yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Modeling with multiple variables: Pancakes | Modeling | Algebra || | Khan Academy


2m read
·Nov 10, 2024

We are told that Jade is making pancakes using flour, eggs, and milk. This table gives the cost per kilogram of each ingredient and the amount in kilograms that Jade uses. All right, the total amount Jade spends on ingredients is six dollars.

Write an equation that relates a, b, c, and d. Pause this video and see if you can have a go at this.

All right, now let's go through this together. So I like to do this in real time so that you can see my thought process. So I'm here with you right now.

So let's see. The total Jade spends, and this is going to be on flour, eggs, and milk, is going to be six dollars. One way to think about it is, and I'll do this in different colors, the flour dollars plus the eggs dollars, or the amount that Jade's going to spend on eggs, plus the amount that Jade spends on milk, I'll call that the milk dollars is going to be equal to the total amount, is going to be equal to six dollars.

So what's the total amount that Jade is going to spend on flour? Well, we can just look right over here: 0.9 dollars per kilogram times 8 kilograms. So Jade is going to spend 0.9 times 8 dollars. I'm just going to multiply these two things to figure out how much Jade spends on flour.

And so this is going to be equal to—I'll lose the dollar symbol just so we can focus on the numbers and the variables—0.9a. 0.9a, and this, of course, is going to be in dollars, which is important. I'm going to add dollars plus dollars plus dollars to get dollars.

Now, what about eggs? Well, the same notion: 0.2 kilograms times b dollars per kilogram. If I take the product of these two, I'm going to get 0.2b dollars, or I could just think of it as 0.2b if I don't write the dollar symbol.

And then last but not least, on milk, let me look at the product of these two things, of this and of this. So d kilograms at c dollars per kilogram, that's just going to be cd dollars.

So, plus cd, and all of that is going to be equal to six dollars. And we're done! We wrote an equation that relates a, b, c, and d.

More Articles

View All
Limits by rationalizing | Limits and continuity | AP Calculus AB | Khan Academy
Let’s see if we can find the limit as x approaches negative one of ( \frac{x + 1}{\sqrt{x + 5} - 2} ). So our first reaction might just be, okay, well let’s just use our limit properties a little bit. This is going to be the same thing as the limit as x …
Frames of reference | Movement and forces | Middle school physics | Khan Academy
When we make new discoveries, we need to be able to share them with others. The first thing we have to do is make sure everyone is on the same page. We do this by using units and frames of reference, which are also called reference frames. We talk about u…
Proof: perpendicular radius bisects chord
So we have this circle called circle O based on the point at its center, and we have the segment OD, and we’re told that segment OD is a radius of circle O. Fair enough! We’re also told that segment OD is perpendicular to this chord, to chord AC, or to se…
Solving unit price problem
We’re told that Nieria earns $75 for four hours of tutoring. How much does Nieria earn for one hour of tutoring? Pause this video and see if you can figure that out. Well, the key here is $75 for four hours of tutoring. There’s a couple of ways you could…
10 TRUTHS YOU NEED TO ACCEPT ABOUT PEOPLE | STOICISM INSIGHTS
Every day, we encounter a sea of faces, each with a narrative that could fill volumes, but despite our close proximity, true comprehension of those around us is frequently just out of reach. What if I told you that behind the diverse manifestations of eve…
Analyzing related rates problems: equations (Pythagoras) | AP Calculus AB | Khan Academy
Two cars are driving towards an intersection from perpendicular directions. The first car’s velocity is 50 kilometers per hour, and the second car’s velocity is 90 kilometers per hour. At a certain instant ( t0 ), the first car is a distance ( X{t0} ) of …