yego.me
💡 Stop wasting time. Read Youtube instead of watch. Download Chrome Extension

Cruise Ship Propulsion | Making the Disney Wish | Mini Episode 2


2m read
·Nov 10, 2024

Our Disney Wish has a new propulsion system. This is definitely a used Azipod, which is an electric motor-driven propeller under the water. It really allows for some amazing performance.

We've made the step from going from a conventional shaft line propeller and rotor to potted propulsion, which means it's a propulsion motor that hangs underneath the ship, and it can turn 360 degrees. Not only are they very, very maneuverable, they're also very hydrodynamically efficient. If you want to stop the ship from going forward, you start closing the engines; this would be stopped engines. So, stop engines in classic propulsion at 0 RPMs is because it's pointing towards each other. Then, if you want to go a stir, you start turning them backwards.

Our Disney Wish has a new propulsion system. There is no shaft line that needs to go into the ship. It gives the naval architect the opportunity to design the half shape of the hull underwater almost freely. So, they can optimize the flow into the propeller in the best possible way.

So, these are big. Right? The propellers are more than six meters. Now, this is two meters, so you can just think six meters in diameter. They're huge!

We're in the ASI powder room, and this is the port Azipod. This is what's making us go forward. The propulsion system is the big buzz, but the other big new feature for us is the LNG system. LNG, of course, is liquid natural gas. It has less emissions, it's cleaner burning, and so all around a better fuel to use. So, we're pleased to be part of that revolution.

We're going to take that LNG on board; it's coming on at -164 degrees C. So, we're dealing with cryogenic technology at the moment. We have two large tanks; they're about the size of 10 school buses. So, we have two tanks that are 10 school buses each. That liquid comes on, so we then transform it into gas to put into the engines. That has an expansion ratio from liquid into gas to 600 times. So, if you think of 10 school buses then expanding 600 times, that's how much gas we have in each tank.

Today is the day where we determine the maximum speed. We start the first measurement.

For us, it's very important to see that she reaches the right speed and that she maneuvers properly.

You exceeded our expectations! The speed tests, the maneuvering trials—she'll use less energy. She is so silent, she'll be sailing more easily. We made sure that she's an awesome ship, and that is everything for us.

Thank you!

More Articles

View All
Limits by rationalizing | Limits and continuity | AP Calculus AB | Khan Academy
Let’s see if we can find the limit as x approaches negative one of ( \frac{x + 1}{\sqrt{x + 5} - 2} ). So our first reaction might just be, okay, well let’s just use our limit properties a little bit. This is going to be the same thing as the limit as x …
Звездообразование в галактиках. Интервью с итальянским астрономом
[Music] Astronomy. The first question: Your work has been published in a very important magazine. It’s well, usually it places really important works. So could you explain why is it so important? Because, as I understand, you observed the situation when s…
Node voltage method (step 5) | Circuit analysis | Electrical engineering | Khan Academy
And now we’re down to solving this circuit. What I want to do now is put in the component values and solve this specific circuit. Let me move the screen up again. We’ll leave the list of steps up there so we can see them. Let’s go to work on this equation…
Managing your bank account | Banking | Financial Literacy | Khan Academy
In this video, we’re going to talk about how it can be very valuable to automate your deposits and your withdrawals into a checking account, and why that actually might be useful. So in the old days, what would typically happen is someone might cut a che…
2015 AP Calculus BC 2a | AP Calculus BC solved exams | AP Calculus BC | Khan Academy
At time ( T ) is greater than or equal to zero, a particle moving along a curve in the XY plane has position ( X(T) ) and ( Y(T) ). So, its x-coordinate is given by the parametric function ( X(T) ) and y-coordinate by the parametric function ( Y(T) ). Wi…
Worked example: Rewriting limit of Riemann sum as definite integral | AP Calculus AB | Khan Academy
So we’ve got a Riemann sum. We’re going to take the limit as n approaches infinity, and the goal of this video is to see if we can rewrite this as a definite integral. I encourage you to pause the video and see if you can work through it on your own. So …